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when read the vocab, if it is a '' character, it will return a hash code -1, compare to the origin source code of google, I found a missing at code code.
if ((vocab[a].cn < min_count)&& (a != 0)) { vocab_size--; free(vocab[a].word); vocab[a].word = NULL; }
it is the &&(a!=0)
The text was updated successfully, but these errors were encountered:
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Jan 8, 2018
when read the vocab, if it is a '' character, it will return a hash code -1, compare to the origin source code of google, I found a missing at code code.
if ((vocab[a].cn < min_count)&& (a != 0)) { vocab_size--; free(vocab[a].word); vocab[a].word = NULL; }it is the &&(a!=0)
The text was updated successfully, but these errors were encountered: