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fixed tex(s)
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dmeoli committed Apr 7, 2021
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13 changes: 11 additions & 2 deletions notebooks/optimization/tex/methods.tex
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Expand Up @@ -11,7 +11,7 @@ \section{Optimization Methods}
$$
\item We say that a differentiable function $f: \Re^m \rightarrow \Re$, i.e., $f \in C^1$, is convex if:
$$
f(x) \geq f(y) + \langle \nabla f(y), x - y \rangle \ \forall \ x, y \in \Re^m
f(x) - f(y) \geq \langle \nabla f(y), x - y \rangle \ \forall \ x, y \in \Re^m
$$
\item We say that a twice differentiable function $f: \Re^m \rightarrow \Re$, i.e., $f \in C^2$ and the Hessian matrix is \emph{symmetric}, is convex iff:
$$
Expand All @@ -28,7 +28,7 @@ \section{Optimization Methods}
is convex for any $\mu > 0$.
If $f$ is differentiable, i.e., $f \in C^1$, this is also equivalent to:
$$
f(y) \geq f(x) + \langle \nabla f(x), y - x \rangle + \frac{\mu}{2} \| y - x \|^2 \ \forall \ x, y \in \Re^m
f(x) - f(y) \geq \langle \nabla f(y), x - y \rangle + \frac{\mu}{2} \| x - y \|^2 \ \forall \ x, y \in \Re^m
$$
and, if $f$ is a twice differentiable function, i.e., $f \in C^2$ and the Hessian matrix is \emph{symmetric}, then $f$ is $\mu$-strongly convex iff:
$$
Expand All @@ -46,6 +46,15 @@ \section{Optimization Methods}
$$
\| \nabla f(x) - \nabla f(y) \| \leq L \| x - y \| \ \forall \ x, y \in \Re^m
$$
or, equivalently:
$$
f(x) - f(y) \leq \langle \nabla f(y), x - y \rangle + \frac{L}{2} \| x - y \|^2 \ \forall \ x, y \in \Re^m
$$
and, if $f$ is a $\mu$-strongly convex function, we give the following Hessian bounds:
$$
\mu I \preceq \nabla^2 f(x) \preceq L I \ \forall \ x \in \Re^m
$$
where $I$ is the identity matrix.
\end{definition}

\pagebreak
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