Peculiar treatment of statements within parentheses

[meijeru]

One is not supposed to put statements within parentheses. Still, I tried the following (printf == print form)

s: 1 (printf s) ; OK compiles and runs as if () were not there
(s: 1) printf s ; idem
(s: 1 printf s) ; "undefined symbol s"
s: 1 (s: s + 1 printf s) ; prints 1, not 2

It looks like only the last of a series of statements and expressions within parenthesis is executed. The others are ignored without warning.

[dockimbel]

Now parentheses are limited to one expression only, more will raise a compilation error. The purpose of parentheses is to mark execution priority in expressions. This behaviour needs to be documented in the upcoming "Expressions" section of the specification.

I am leaving the issue open until the specification is updated.

[meijeru]

The fix is not complete: the following compiles OK while I think it should not

i: 1 (i: i + 1) printf i ; result is 2

[dockimbel]

Tested OK.