Getting the generic type of the wrapping function

[yavulan]

Thank you for this awesome project!

I want foo function to generate ts code depending on the generic type passed when calling this function.
Is it possible for ts-morph to get the generic type of the wrapping function?

function foo<T>() {
  // ts-morph methods to get the current generic type, e.g. "string" in case called `foo<string>()`
  // ...
}

In case it is not possible, is there other way to pass the type to the ts-morph inside the body of the function? Maybe through the type of an argument or something else?

Thank you!

[dsherret]

Hey @yavulan, if I'm understanding correctly, I believe probably the easiest way to solve this is to just change all the the call sites like foo<number>() to have the necessary code. I think you could just replace the expressions with an immediately invoked function containing the specify logic (ex. replace foo<string>() with (() => { /* your code goes here that deals with string */ })()). The node.replaceWith(writer => {}) function will be useful here.

By the way, here's an example that uses the compiler api directly and babel to change the call sties: https://github.com/dsherret/ts-nameof (doesn't use ts-morph)

[yavulan]

Thank you. ts-nameof example is very close to what I was looking for. It's a pity microsoft/TypeScript#14419 is still not implemented.

Btw, I went through some issues on the issue tracker for ts-morph. And it's incomparable to most issue trackers for popular libraries - this issue tracker is very welcoming and useful. THANK YOU!