Given a singly linked list, determine if it is a palindrome.
Example 1:
Input: 1->2 Output: false
Example 2:
Input: 1->2->2->1 Output: true
Follow up: Could you do it in O(n) time and O(1) space?
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
class Solution {
public boolean isPalindrome(ListNode head) {
if(head == null || head.next == null)
return true;
ListNode p1 = clone(head);
ListNode p2 = reverse(head);
while(p1 != null) {
if(p1.val != p2.val)
return false;
p1 = p1.next;
p2 = p2.next;
}
return true;
}
private ListNode clone(ListNode head) {
ListNode cloneHead = null;
ListNode prev = null;
ListNode current = head;
while(current != null) {
ListNode listnode = new ListNode(current.val);
if(cloneHead == null) {
cloneHead = listnode;
}
if(prev != null) {
prev.next = listnode;
}
prev = listnode;
current = current.next;
}
return cloneHead;
}
private ListNode reverse(ListNode head) {
ListNode current = head;
ListNode prev = null;
while(current != null) {
ListNode tmp = current.next;
current.next = prev;
prev = current;
current = tmp;
}
return prev;
}
}