How to define discovery.zen.ping.unicast.hosts

[UnderGreen]

I did't see documentation here about defining parameter discovery.zen.ping.unicast.hosts.
If I understood - need to define string like '["host1", "host2"]'. But I want to do it via chef search. I should write my own lwrp for this goal?

[martinb3]

Hi @UnderGreen -- I apologize I didn't respond sooner. Right now, this is just a single string, e.g. host1, host2, .... There are some issues parsing YAML lists in ES itself, see #419 (as well as elastic/elasticsearch#13592 and elastic/elasticsearch#13954).

As far as using Chef search, this cookbook doesn't currently have an opinion about the best way to derive the list of unicast hosts. If we included a Chef search recipe that did so, we'd get into a few different problems -- how to find other nodes (tags? runlists? etc), should it be a default behavior, as well as how to override the behavior. We had this in a previous version and it was fraught with peril :)

[martinb3]

I'd like to leave this open so we can provide an example in the docs of using Chef search, even if we don't provide an implementation 👍

[paulheijman]

This is how we do it at the moment:

default.rb

elk_nodes = '["' + search(:node, 'role:elasticsearch-datanode').map(&:ipaddress).sort.uniq.join('", "') + '"]'
elasticsearch_configure 'elasticsearch' do
    configuration ({
        'cluster.name' => 'cluster-01',
        'path.data' => '/es/data',
        'path.logs' => '/es/logs',
        'network.host' => '_bond0_',
        'discovery.zen.ping.multicast.enabled' => 'false',
        'discovery.zen.ping.unicast.hosts' => elk_nodes
    })
end

Make sure your chef nodes have the correct role (elasticsearch-datanode in this case). To verify which hosts are being included run
knife search node 'roles:elasticsearch-datanode'

[UnderGreen]

Thank you!

[wheelq]

How does this work with password protected ES nodes?

[martinb3]

Hi @wheelq -- can you open a new issue? This one has been closed for more than 2 years. Please cite exactly what setting you're asking about, too. Thanks!