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* Resolve the missing refs only after the aggregate tree is resolved (cherry picked from commit 10167b1)
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54 changes: 54 additions & 0 deletions
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x-pack/plugin/sql/qa/src/main/resources/subselect.sql-spec
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| Original file line number | Diff line number | Diff line change |
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| @@ -0,0 +1,54 @@ | ||
| // To mute tests follow example in file: example.sql-spec | ||
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| simpleSubSelect | ||
| SELECT first_name, last_name FROM (SELECT * FROM test_emp); | ||
| simpleSubSelectWithProjection | ||
| SELECT first_name, last_name FROM (SELECT first_name, last_name FROM test_emp); | ||
| simpleSubSelectWithAliasedProjection | ||
| SELECT last_name, f FROM (SELECT first_name AS f, last_name FROM test_emp); | ||
| simpleSubSelectWithCondition | ||
| SELECT first_name, last_name FROM (SELECT * FROM test_emp WHERE gender IS NOT NULL) ORDER BY first_name NULLS first; | ||
| simpleSubSelectWithOrderByAlias | ||
| SELECT last_name, f FROM (SELECT first_name AS f, last_name FROM test_emp) ORDER BY f DESC NULLS last; | ||
| simpleSubSelectWithOrderByFieldName | ||
| SELECT last_name, f FROM (SELECT first_name AS f, last_name FROM test_emp) ORDER BY last_name ASC; | ||
| simpleSubSelectWithGroupBy | ||
| SELECT gender FROM (SELECT first_name AS f, last_name, gender FROM test_emp) GROUP BY gender ORDER BY gender ASC; | ||
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| subSelectWithCountAndComplexCondition | ||
| SELECT COUNT(*) as c FROM (SELECT * FROM test_emp WHERE gender IS NOT NULL) WHERE ABS(salary) > 0 GROUP BY gender ORDER BY gender; | ||
| subSelectWithCountAndGroupBy | ||
| SELECT COUNT(*), gender FROM (SELECT first_name AS f, last_name, gender FROM test_emp) GROUP BY gender ORDER BY gender ASC; | ||
| subSelectWithCountAndMax | ||
| SELECT COUNT(*), gender, MAX("salary") FROM (SELECT first_name AS f, last_name, gender, salary FROM test_emp) GROUP BY gender ORDER BY gender ASC; | ||
| subSelectWithCountAndMultipleAggregates | ||
| SELECT COUNT(*), gender, MAX("salary"), MAX(salary) m, MIN("salary") FROM (SELECT first_name AS f, last_name, gender, salary FROM test_emp) GROUP BY gender ORDER BY gender ASC; | ||
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| subSelectWithCastAndGroupBy | ||
| SELECT TRUE as employed, gender g, CAST(SUM(emp_no) AS BIGINT) s FROM (SELECT * FROM test_emp) GROUP BY g ORDER BY g DESC; | ||
| subSelectWithCastAndGroupByAndLiteralsInSubQuery | ||
| SELECT TRUE as employed, gender g, CAST(SUM(emp_no) AS BIGINT) s FROM (SELECT TRUE, FALSE, gender, emp_no FROM test_emp) GROUP BY g ORDER BY g ASC; | ||
| subSelectWithLiteralsAndConditionInSubQuery | ||
| SELECT 10, 'foo', COUNT(*), '20', 'bar' FROM (SELECT * FROM test_emp WHERE gender = 'M') GROUP BY gender ORDER BY 3; | ||
| subSelectWithSameConditionInQueryAndSubQuery | ||
| SELECT emp_no e, 5 FROM (SELECT * FROM test_emp WHERE emp_no < 10020) WHERE emp_no < 10020 GROUP BY e ORDER BY emp_no DESC; | ||
| subSelectWithHavingWithCount | ||
| SELECT languages, COUNT(*) c FROM (SELECT languages FROM test_emp WHERE languages > 2 AND gender IS NOT NULL) GROUP BY languages HAVING COUNT(*) IS NOT NULL ORDER BY languages DESC; | ||
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| subSelectWithConditionOnCountAndMultipleConditions | ||
| SELECT MIN("salary") min, MAX("salary") max, gender g, languages l, COUNT(*) c FROM (SELECT last_name, salary, languages, gender, first_name FROM test_emp WHERE languages > 3) WHERE languages < 5 GROUP BY g, languages HAVING c > 4 ORDER BY gender, languages; | ||
| subSelectWithCountDistinct | ||
| SELECT gender, COUNT(DISTINCT languages) AS c FROM (SELECT * FROM test_emp) GROUP BY gender HAVING count(DISTINCT languages) > 0 ORDER BY gender; | ||
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| subSelectWithNoMatchCondition | ||
| SELECT last_name l FROM (SELECT last_name FROM test_emp) WHERE 1 = 2 ORDER BY 1 LIMIT 10; | ||
| subSelectWithNoMatchConditionInSubQuery | ||
| SELECT last_name l FROM (SELECT last_name FROM test_emp WHERE 1 = 2) WHERE 1 = 1 ORDER BY 1 LIMIT 10; | ||
| subSelectWithMatchInSubQueryAndNoMatchInRootQuery | ||
| SELECT last_name l FROM (SELECT last_name FROM test_emp WHERE TRUE) WHERE 1 = 1 ORDER BY 1 LIMIT 10; | ||
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| subSelectWithGreatestOrderBy | ||
| SELECT GREATEST(10096, ABS(emp_no + 1)) AS gt FROM (SELECT * FROM test_emp) ORDER BY gt LIMIT 10; | ||
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| subSelectWithInAndIsNotNull | ||
| SELECT NOT((languages = 2) IS NULL) AS col1, NOT((languages = 2) IS NOT NULL) AS col2 FROM (SELECT * FROM test_emp WHERE emp_no IN (10019, 10020, 10021)) WHERE emp_no IN (10018, 10019, 10020) ORDER BY emp_no; |
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