docs: Fix the syntax error for code fragment (#37960)

By using `app.on('ready').then(xxx)`, application will throw a TypeError

Co-authored-by: trop[bot] <37223003+trop[bot]@users.noreply.github.com>
Co-authored-by: Zenkie Bear <62818957+ZenkieBear@users.noreply.github.com>

docs/tutorial/tutorial-2-first-app.md

@@ -274,7 +274,7 @@ calling `createWindow()` once its promise is fulfilled.
 You typically listen to Node.js events by using an emitter's `.on` function.
 
 ```diff
-+ app.on('ready').then(() => {
++ app.on('ready', () => {
 - app.whenReady().then(() => {
   createWindow()
 })