Can I call an actual method of a "mocked" object?

[jpeterman1]

Sometimes it can be convenient to use the methods of the real underlying class that is being mocked rather that having to stub out everything. Is that possible with FakeIt?

Thanks,
JP

[eranpeer]

Thank you for trying FakeIt.
Currently, FakeIt doesn't support spying an object or partially mocking a
class.
I'm looking for a technical solution that will enable spying in both GCC
and MSC++.
Hopefully, I'll be able to support spying soon.

Regards,
Eran.

On Tue, Jun 3, 2014 at 6:39 AM, jpeterman1 notifications@github.com wrote:

Sometimes it can be convenient to use the methods of the real underlying
class that is being mocked rather that having to stub out everything. Is
that possible with FakeIt?

Thanks,
JP

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Reply to this email directly or view it on GitHub
#1.

Eran
972-52-8387550

[eranpeer]

I added spying functionality. It is now possible to spy an object by simply writing:

SomeClass obj;
Mock<SomeClass> spy(obj);

Here is the complete example:

struct SomeClass {
    virtual int func1(int arg) {
        return arg;
    }
    virtual int func2(int arg) {
        return arg;
    }
};

void useOriginalClassMethodIfNotStubbed() {
    SomeClass obj;
    Mock<SomeClass> spy(obj);
    When(spy[&SomeClass::func1]).Return(0); // Override func1 to return 0.
    SomeClass& i = spy.get();
    ASSERT_EQUAL(0, i.func1(1)); // func1 should return 0 
    ASSERT_EQUAL(1, i.func2(1)); // func2 should stay unmocked
}

You can check for more examples at tests/spying_tests.cpp