Fix: operator-assignment with parenthesized expression (fixes #8190) (

#8197)
eslint · Mar 6, 2017 · 41e3d9c · 41e3d9c
1 parent 5e3bca7
commit 41e3d9c
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Showing 2 changed files with 6 additions and 1 deletion.
diff --git a/lib/rules/operator-assignment.js b/lib/rules/operator-assignment.js
@@ -135,7 +135,7 @@ module.exports = {
                                 const equalsToken = getOperatorToken(node);
                                 const operatorToken = getOperatorToken(expr);
                                 const leftText = sourceCode.getText().slice(node.range[0], equalsToken.range[0]);
-                                const rightText = sourceCode.getText().slice(operatorToken.range[1], node.range[1]);
+                                const rightText = sourceCode.getText().slice(operatorToken.range[1], expr.right.range[1]);
 
                                 return fixer.replaceText(node, `${leftText}${expr.operator}=${rightText}`);
                             }

diff --git a/tests/lib/rules/operator-assignment.js b/tests/lib/rules/operator-assignment.js
@@ -149,6 +149,11 @@ ruleTester.run("operator-assignment", rule, {
         output: "x += y",
         options: ["always"],
         errors: EXPECTED_OPERATOR_ASSIGNMENT
+    }, {
+        code: "x = (x + y)",
+        output: "x += y",
+        options: ["always"],
+        errors: EXPECTED_OPERATOR_ASSIGNMENT
     }, {
         code: "x += y",
         output: "x = x + y",