[Question] dsl::integer and negative numbers

[facontidavide]

Hi,

I notice that dsl::integer is not parsing negative numbers. Is that the desired behavior?

I am not sure how to address this. This is my sample code:

#include <lexy/action/parse.hpp>
#include <lexy/callback.hpp>
#include <lexy/dsl.hpp>
#include <lexy_ext/report_error.hpp>
#include <lexy/input/string_input.hpp>

namespace dsl = lexy::dsl;

struct production
{
  static constexpr auto whitespace = dsl::ascii::space;

  static constexpr auto rule =
      [] {
        auto integer = dsl::integer<int64_t>;
        auto hex_integer = LEXY_LIT("0x") >> dsl::integer<int, dsl::hex>;

        return (hex_integer | integer) + dsl::eof;
      }();
  static constexpr auto value = lexy::forward<int>;
};

int main()
{
  const char* strings[] = {"7", "0x78", "-7"};
  for( const auto& str: strings )
  {
    auto input  = lexy::zstring_input(str);
    auto result = lexy::parse<production>(input, lexy_ext::report_error);
    if (result.has_value())
    {
      std::printf("%d\n", result.value());
    }
  }
  return 0;
}

Output:

7
120
error: while parsing Integer
     |
   1 | -7
     | ^ exhausted choice

[facontidavide]

I found the solution looking at the json example, but I am not quite sure why the dsl::peek is required.

struct production
{
  struct integer
  {
    static constexpr auto rule = dsl::sign + dsl::integer<int64_t>;
    static constexpr auto value = lexy::as_integer<int64_t>;
  };

  static constexpr auto rule = [] {
    auto hex_integer = LEXY_LIT("0x") >> dsl::integer<int64_t, dsl::hex>;
    auto regular_integer = dsl::peek(dsl::lit_c<'-'> / dsl::lit_c<'+'> / dsl::digit<>) >> dsl::p<integer>;
    return ( hex_integer | regular_integer ) + dsl::eof;
  }();

  static constexpr auto value = lexy::forward<int64_t>;
};