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log1mexp(x) = log(1 - exp(-x))
According to this CRAN note it should be evaluated using either log1p or expm1 depending on some threshold value of x. Maybe I will add this. Just an editorial comment, the name is a little funky because you might think it would compute log(1 - exp(x)).
The text was updated successfully, but these errors were encountered:
log1mexp(x) = log(1 - exp(-x))
According to this CRAN note it should be evaluated using either log1p or expm1 depending on some threshold value of x. Maybe I will add this. Just an editorial comment, the name is a little funky because you might think it would compute log(1 - exp(x)).
The text was updated successfully, but these errors were encountered: