Only use Makefile to release

The release procedure looks like:

1. Create release commit (by Timo/Gabriel) - Message: "release: vX.X.X"
    1.1 Update CHANGELOG.md
    1.2 Update version in sure/core.py
2. Tag release commit (by Timo/Gabriel) - Tag: vX.X.X
3. Checkout release commit by tag vX.X.X
4. Run "make release"
    4.1 Will clean repository
    4.2 Will test
    4.3 Will generate README.rst
    4.4 Will publish to PyPI

The .release script is not used anymore

.gitignore

@@ -1,11 +1,20 @@
+# python bytecode
 *.pyc
-.coverage
+__pycache__
+
+# pip and setuptools
 docs/_build
 build/
 dist/
-sure.egg-info/
+*.egg-info/
+sure-*.tar.gz
+README.rst
+
+# temporary test files and dirs
+.coverage
 .tox
+
+# temporary editor files
 *.sublime-project
 *.sublime-workspace
-sure-*.tar.gz
 *.swp

Makefile

@@ -17,9 +17,9 @@ export SURE_NO_COLORS := true
 install_deps:
 	@pip install -r development.txt
 
-test:
+test: readme
 	@python setup.py build
-	@nosetests -s --verbosity=2 tests --rednose
+	@tox
 	@steadymark OLD_API.md
 	@steadymark README.md
 
@@ -28,15 +28,18 @@ clean:
 	@for pattern in `cat .gitignore`; do rm -rf $$pattern; find . -name "$$pattern" -exec rm -rf {} \;; done
 	@echo "OK!"
 
+
+readme:
+	@pandoc README.md --from markdown --to rst -o README.rst
+
+publish: readme
+	@python setup.py sdist register upload
+
 release: clean test publish
 	@printf "Exporting to $(filename)... "
-	@tar czf $(filename) sure setup.py README.md COPYING
+	@tar czf $(filename) sure setup.py README.md README.rst COPYING
 	@echo "DONE!"
 
-publish:
-	@./.release
-	@python setup.py sdist register upload
-
 acceptance: clean
 	@steadymark README.md
 	@steadymark spec/reference.md