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binary_watch.py
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binary_watch.py
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"""
401. 二进制手表
位运算 回溯
简单
二进制手表顶部有 4 个 LED 代表 小时(0-11),底部的 6 个 LED 代表 分钟(0-59)。每个 LED 代表一个 0 或 1,最低位在右侧。
例如,下面的二进制手表读取 "3:25" 。
(图源:WikiMedia - Binary clock samui moon.jpg ,许可协议:Attribution-ShareAlike 3.0 Unported (CC BY-SA 3.0) )
给你一个整数 turnedOn ,表示当前亮着的 LED 的数量,返回二进制手表可以表示的所有可能时间。你可以 按任意顺序 返回答案。
小时不会以零开头:
例如,"01:00" 是无效的时间,正确的写法应该是 "1:00" 。
分钟必须由两位数组成,可能会以零开头:
例如,"10:2" 是无效的时间,正确的写法应该是 "10:02" 。
示例 1:
输入:turnedOn = 1
输出:["0:01","0:02","0:04","0:08","0:16","0:32","1:00","2:00","4:00","8:00"]
示例 2:
输入:turnedOn = 9
输出:[]
提示:
0 <= turnedOn <= 10
来源:力扣(LeetCode)
链接:https://leetcode.cn/problems/binary-watch
"""
from typing import List
class Solution:
def readBinaryWatch(self, turnedOn: int) -> List[str]:
ans = list()
for h in range(12):
for m in range(60):
if bin(h).count("1") + bin(m).count("1") == turnedOn:
ans.append(f"{h}:{m:02d}")
return ans
if __name__ == '__main__':
solution = Solution()
result = solution.readBinaryWatch(1)
print(result)
assert result == ["0:01", "0:02", "0:04", "0:08", "0:16", "0:32", "1:00", "2:00", "4:00", "8:00"]
result = solution.readBinaryWatch(9)
print(result)
assert result == []