fix(challenges): typos in some basic node and express challenges

fixed a typo in serve static assets challenge and in chain middleware to create a time server

ISSUES CLOSED: freeCodeCamp#113, freeCodeCamp#114

challenges/05-apis-and-microservices/basic-node-and-express.json

@@ -69,7 +69,7 @@
       "id": "587d7fb0367417b2b2512bf0",
       "title": "Serve Static Assets",
       "description": [
-        "An HTML server usually has one or more directories that are accessible by the user. You can place there the static assets needed by your application (stylesheets, scripts, images). In Express you can put in place this functionality using the middleware <code>express.static(path)</code>, where the parameter is the absolute path of the folder containing the assets. If don’t know what a middleware is, don’t worry. We’ll discuss about it later in details. Basically middlewares are functions that intercept route handlers, adding some kind of information. A middleware needs to be mounted using the method <code>app.use(path, middlewareFunction)</code>. The first path argument is optional. If you don’t pass it, the middleware will be executed for all the requests.",
+        "An HTML server usually has one or more directories that are accessible by the user. You can place there the static assets needed by your application (stylesheets, scripts, images). In Express you can put in place this functionality using the middleware <code>express.static(path)</code>, where the parameter is the absolute path of the folder containing the assets. If you don’t know what a middleware is, don’t worry. We’ll discuss about it later in details. Basically middlewares are functions that intercept route handlers, adding some kind of information. A middleware needs to be mounted using the method <code>app.use(path, middlewareFunction)</code>. The first path argument is optional. If you don’t pass it, the middleware will be executed for all the requests.",
         "Mount the <code>express.static()</code> middleware for all the requests with <code>app.use()</code>. The absolute path to the assets folder is <code>__dirname + /public</code>.",
         "Now your app should be able to serve a CSS stylesheet. From outside the public folder will appear mounted to the root directory. Your front-page should look a little better now!"
       ],
@@ -151,7 +151,7 @@
       "description": [
         "Middleware can be mounted at a specific route using <code>app.METHOD(path, middlewareFunction)</code>. Middleware can also be chained inside route definition.",
         "Look at the following example:",
-        "<blockquote>app.get('/user', function(req, res, next) {<br>  req.user = getTheUserSync();  // Hypotetical synchronous operation<br>  next();<br>}, function(req, res) {<br>  res.send(req.user);<br>})</blockquote>",
+        "<blockquote>app.get('/user', function(req, res, next) {<br>  req.user = getTheUserSync();  // Hypothetical synchronous operation<br>  next();<br>}, function(req, res) {<br>  res.send(req.user);<br>})</blockquote>",
         "This approach is useful to split the server operations into smaller units. That leads a to a better app structure, and the possibility to reuse code in different places. This approach can also be used to perform some validation on the data. At each point of the middleware stack you can block the execution of the current chain and pass control to functions specifically designed to handle errors. Or you can pass control to the next matching route, to handle special cases. We will see how in the advanced Express section.",
         "In the route <code>app.get('/now', ...)</code> chain a middleware function and the final handler. In the middleware function you should add the current time to the request object in the <code>req.time</code> key. You can use <code>new Date().toString()</code>. In the handler, respond with a JSON object, taking the structure <code>{time: req.time}</code>.",
         "Hint: The test will not pass if you don’t chain the middleware. If you mount the function somewhere else, the test will fail, even if the output result is correct."