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Add a "checkout-cache" command which does what the name suggests.
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I'll also eventually change "read-tree" to only update the cache
information, instead of doing a checkout of the tree. Much nicer.
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Linus Torvalds committed Apr 9, 2005
1 parent 734aab7 commit 33db5f4
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6 changes: 5 additions & 1 deletion Makefile
@@ -1,7 +1,8 @@
CFLAGS=-g -O3 -Wall
CC=gcc

PROG=update-cache show-diff init-db write-tree read-tree commit-tree cat-file fsck-cache
PROG= update-cache show-diff init-db write-tree read-tree commit-tree \
cat-file fsck-cache checkout-cache

all: $(PROG)

Expand Down Expand Up @@ -33,6 +34,9 @@ cat-file: cat-file.o read-cache.o
fsck-cache: fsck-cache.o read-cache.o
$(CC) $(CFLAGS) -o fsck-cache fsck-cache.o read-cache.o $(LIBS)

checkout-cache: checkout-cache.o read-cache.o
$(CC) $(CFLAGS) -o checkout-cache checkout-cache.o read-cache.o $(LIBS)

read-cache.o: cache.h
show-diff.o: cache.h

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140 changes: 140 additions & 0 deletions checkout-cache.c
@@ -0,0 +1,140 @@
/*
* Check-out files from the "current cache directory"
*
* Copyright (C) 2005 Linus Torvalds
*
* Careful: order of argument flags does matter. For example,
*
* checkout-cache -a -f file.c
*
* Will first check out all files listed in the cache (but not
* overwrite any old ones), and then force-checkout "file.c" a
* second time (ie that one _will_ overwrite any old contents
* with the same filename).
*
* Also, just doing "checkout-cache" does nothing. You probably
* meant "checkout-cache -a". And if you want to force it, you
* want "checkout-cache -f -a".
*
* Intuitiveness is not the goal here. Repeatability is. The
* reason for the "no arguments means no work" thing is that
* from scripts you are supposed to be able to do things like
*
* find . -name '*.h' -print0 | xargs -0 checkout-cache -f --
*
* which will force all existing *.h files to be replaced with
* their cached copies. If an empty command line implied "all",
* then this would force-refresh everything in the cache, which
* was not the point.
*
* Oh, and the "--" is just a good idea when you know the rest
* will be filenames. Just so that you wouldn't have a filename
* of "-a" causing problems (not possible in the above example,
* but get used to it in scripting!).
*/
#include "cache.h"

static int force = 0, quiet = 0;

static int write_entry(struct cache_entry *ce)
{
int fd;
void *new;
unsigned long size;
long wrote;

new = read_sha1_file(ce->sha1, "blob", &size);
if (!new) {
fprintf(stderr, "checkout-cache: unable to read sha1 file of %s (%s)",
ce->name, sha1_to_hex(ce->sha1));
return -1;
}
fd = open(ce->name, O_WRONLY | O_CREAT | O_TRUNC, 0600);
if (fd < 0) {
fprintf(stderr, "checkout-cache: unable to create %s (%s)",
ce->name, strerror(errno));
free(new);
return -1;
}
wrote = write(fd, new, size);
close(fd);
free(new);
if (wrote == size)
return 0;
fprintf(stderr, "checkout-cache: unable to write %s", ce->name);
return -1;
}

static int checkout_entry(struct cache_entry *ce)
{
if (!force) {
struct stat st;

if (!stat(ce->name, &st)) {
unsigned changed = cache_match_stat(ce, &st);
if (!changed)
return 0;
if (!quiet)
fprintf(stderr, "checkout-cache: %s already exists", ce->name);
return -1;
}
}
return write_entry(ce);
}

static int checkout_file(const char *name)
{
int pos = cache_name_pos(name, strlen(name));
if (pos < 0) {
if (!quiet)
fprintf(stderr, "checkout-cache: %s is not in the cache", name);
return -1;
}
return checkout_entry(active_cache[pos]);
}

static int checkout_all(void)
{
int i;

for (i = 0; i < active_nr ; i++) {
struct cache_entry *ce = active_cache[i];
if (checkout_entry(ce) < 0)
return -1;
}
return 0;
}

int main(int argc, char **argv)
{
int i, force_filename = 0;

if (read_cache() < 0) {
fprintf(stderr, "Invalid cache");
exit(1);
}

for (i = 1; i < argc; i++) {
const char *arg = argv[i];
if (!force_filename) {
if (!strcmp(arg, "-a")) {
checkout_all();
continue;
}
if (!strcmp(arg, "--")) {
force_filename = 1;
continue;
}
if (!strcmp(arg, "-f")) {
force = 1;
continue;
}
if (!strcmp(arg, "-q")) {
quiet = 1;
continue;
}
}
checkout_file(arg);
}
return 0;
}

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