How to initialize a task without first run?

[hwebb]

For example I have the task set like: s.Every(60).Minutes().SingletonMode().Do(task)
I'll probably have many of the above launching at different intervals, some takes a long time to run. I initialize all of them at launch of the script, but at the moment I launch the script, all of the tasks run at once a first time, then after that initial run it all goes to place, but I would like to avoid running everything at once as it could be resource intensive at that moment and would run things I don't necessarily want to run right now.
Am I doing it wrong?

[JohnRoesler]

Hi @hwebb you can set the individual job or the entire scheduler to wait for the first interval before running rather than running immediately.

s.Every(60).Minutes().WaitForSchedule().Do(task)

or

s.WaitForScheduleAll()
s.Every(60).Minutes().Do(task)

The SinglettonMode() is relevant when you have long running tasks that may run longer than the scheduled interval.

References:
https://pkg.go.dev/github.com/go-co-op/gocron#Scheduler.WaitForSchedule
https://pkg.go.dev/github.com/go-co-op/gocron#Scheduler.WaitForScheduleAll
https://pkg.go.dev/github.com/go-co-op/gocron#Scheduler.SingletonMode

[hwebb]

Thanks, I wonder how I missed that.

[JohnRoesler]

If you any suggestions on how to make it more clear - I would appreciate that! I want the documentation to be easy to follow!