reflect.InterfaceValue does not have Implements(*reflect.InterfaceType) bool method #327
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Given a reflect.Value v and a desire to see if the underlying object implements
interface Foo,
use the value's Interface() method to extract an interface object that can be tested
using a type
assertion.
if foo, ok := v.Interface().(Foo) {
use foo
}
That should give you what you need.
-rob
Status changed to WontFix. |
You don't really need the conditional set, just the test. Owner changed to r...@golang.org. Status changed to LongTerm. |
|
This issue was closed by revision e1ee3b5. Status changed to Fixed. |
This issue was closed.
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by wmundt42:
There is currently no way, via the reflection interface, to do a conditional set. Such a set would have the semantics of the two-result type assertion in the language itself, but would allow the use of such semantics on types passed around as variables. Proposed semantics: func (v *InterfaceValue) ConditionalSet(x Value) (ok bool) { if x implements v or x is the zero interface value { set v to x; returns true; } else { set v to zero interface value; return false; } } This would allow reflection-based checks on whether a value implements an interface, and also (by construction of zero Value instances) whether any reflect.Type implements a particular reflect.InterfaceType without having to iterate the methods and evaluate the logic manually.The text was updated successfully, but these errors were encountered: