<page_title> 1860 United States presidential election in Iowa </page_title> <section_title> Results </section_title> <table> <cell> Republican <col_header> Party </col_header> </cell> <cell> Abraham Lincoln <col_header> Candidate </col_header> </cell> <cell> 54.61% <col_header> % </col_header> </cell> <cell> Democratic <col_header> Party </col_header> </cell> <cell> Stephen A. Douglas <col_header> Candidate </col_header> </cell> <cell> 43.22% <col_header> % </col_header> </cell> </table>
Iowa was won by Abraham Lincoln (R), with 54.61% of the popular vote against Senator Stephen A. Douglas (D), with 43.22% of the popular vote.