<page_title> 1844 United States presidential election in Rhode Island </page_title> <section_title> Results </section_title> <table> <cell> Henry Clay of Kentucky <col_header> United States presidential election in Rhode Island, 1844 </col_header> <col_header> Candidate </col_header> <col_header> Count </col_header> </cell> <cell> 59.55% <col_header> United States presidential election in Rhode Island, 1844 </col_header> <col_header> Popular vote </col_header> </cell> </table>
In 1844 United States presidential election, Henry Clay won 59.55% of the popular vote in Rhode Island.