<page_title> 1894 United States House of Representatives election in Wyoming </page_title> <section_title> Results </section_title> <table> <cell> Republican <col_header> Party </col_header> </cell> <cell> Frank Wheeler Mondell <col_header> Candidate </col_header> </cell> <cell> 52.64% <col_header> % </col_header> </cell> <cell> Democratic <col_header> Party </col_header> </cell> <cell> Henry A. Coffeen <col_header> Candidate </col_header> </cell> <cell> 32.17% <col_header> % </col_header> </cell> <cell> People's <col_header> Party </col_header> </cell> <cell> Shakespeare E. Sealey <col_header> Candidate </col_header> </cell> </table>
Republican Frank Wheeler Mondell defeated Democrat Henry A. Coffeen and Populist Shakespeare E. Sealey, receiving 52.64% of the vote, making Coffeen the second Representative from Wyoming to lose the election.