Omit field when using derive GraphQLObject

[sporto]

I have a struct like (which doubles as a diesel model):

#[derive(Queryable, GraphQLObject, Debug)]
pub struct User {
	pub id: i32,
	pub email: String,
	pub password_hash: String,
	...
}

I would like to omit password_hash in the generated GraphQl type.
Is this possible at the moment or do I have to create another Struct?
A way of omitting some fields would be great.

Thanks.

[piperRyan]

While there isn't a way to omit a field like serde's skip_serializing , but I think one should be able to do this like so:

#[derive(Queryable, Debug)]
pub struct User {
	pub id: i32,
	pub email: String,
	pub password_hash: String,
	...
}

graphql_object!(User: () |&self| {
    description: "A user in the database"

    field id() -> &i32 as "The user's unique identifier" {
        &self.id
    }

    field email() -> &String as "The user's email" {
        &self.email
    }

   ... other fields to expose leaving out password_hash
});

However, I have to admit I haven't tried this.