Set protocolVersion as optional in escape function (TypeScript)

[Rafatcb]

As you can see below, it is already an optional argument, so I'm just fixing TypeScript types.

node-firebird/lib/index.js

Lines 830 to 857 in 9613cd4

	/**
	* Escape value
	* @param {Object} value
	* @param {Number} protocolVersion (optional, default: PROTOCOL_VERSION13)
	* @return {String}
	*/
	exports.escape = function(value, protocolVersion) {
	if (value === null || value === undefined)
	return 'NULL';
	switch (typeof(value)) {
	case 'boolean':
	if ((protocolVersion || PROTOCOL_VERSION13) >= PROTOCOL_VERSION13)
	return value ? 'true' : 'false';
	else
	return value ? '1' : '0';
	case 'number':
	return value.toString();
	case 'string':
	return "'" + value.replace(/'/g, "''").replace(/\\/g, '\\\\') + "'";
	}
	if (value instanceof Date)
	return "'" + value.getFullYear() + '-' + (value.getMonth()+1).toString().padLeft(2, '0') + '-' + value.getDate().toString().padLeft(2, '0') + ' ' + value.getHours().toString().padLeft(2, '0') + ':' + value.getMinutes().toString().padLeft(2, '0') + ':' + value.getSeconds().toString().padLeft(2, '0') + '.' + value.getMilliseconds().toString().padLeft(3, '0') + "'";
	throw new Error('Escape supports only primitive values.');
	};

[mariuz]

Thank you for contribution !