Jinjava clear file

[Academic-123]

Please help on this issue
https://ru.stackoverflow.com/questions/1413804/jinjava-%d0%be%d1%87%d0%b8%d1%89%d0%b0%d0%b5%d1%82-%d1%84%d0%b0%d0%b9%d0%bb

[jasmith-hs]

This will happen if you have an interpreter with a different config on the stack (in this case, one that has isFailOnUnknownTokens() == false)

    JinjavaInterpreter parentInterpreter = JinjavaInterpreter.getCurrent();
    if (parentInterpreter != null) {
      renderConfig = parentInterpreter.getConfig();
      ...
    }

    JinjavaInterpreter interpreter = globalConfig
      .getInterpreterFactory()
      .newInstance(this, context, renderConfig);
    JinjavaInterpreter.pushCurrent(interpreter);
    try {
      String result = interpreter.render(template);

renderConfig will get overridden with the parent interpreter's config if there is an interpreter on the stack, rather than just the jinjava.getGlobalConfig()

Try calling JinjavaInterpreter.popCurrent() before the code block in the StackOverflow question and see if it works properly

[Academic-123]

This will happen if you have an interpreter with a different config on the stack (in this case, one that has isFailOnUnknownTokens() == false)

    JinjavaInterpreter parentInterpreter = JinjavaInterpreter.getCurrent();
    if (parentInterpreter != null) {
      renderConfig = parentInterpreter.getConfig();
      ...
    }

    JinjavaInterpreter interpreter = globalConfig
      .getInterpreterFactory()
      .newInstance(this, context, renderConfig);
    JinjavaInterpreter.pushCurrent(interpreter);
    try {
      String result = interpreter.render(template);

renderConfig will get overridden with the parent interpreter's config if there is an interpreter on the stack, rather than just the jinjava.getGlobalConfig()

Try calling JinjavaInterpreter.popCurrent() before the code block in the StackOverflow question and see if it works properly

Now I get hostname={{host}} if the context does not have the necessary variable, how to make it throw an error if the required variable is not found in context?

[jasmith-hs]

Are there more details to your setup. The render result should have a blank output and it should have an error in renderResult.getErrors(). Are there no FATAL errors in your RenderResult?

[Academic-123]

Are there more details to your setup. The render result should have a blank output and it should have an error in renderResult.getErrors(). Are there no FATAL errors in your RenderResult?

Yesterday I used JinjavaInterpeter.popCurrent(); and everything worked, but today it again clears the file, tell me what might be the problem? I understand that sounds unreasonable but I did even mvn clean, and did Invalidate Cache

[jasmith-hs]

while(JinjavaInterpreter.getCurrent() != null) {
    JinjavaInterpreter.popCurrent();
}

Maybe doing this will help.

[Academic-123]

while(JinjavaInterpreter.getCurrent() != null) {
    JinjavaInterpreter.popCurrent();
}

Maybe doing this will help.

Does not help.

[jasmith-hs]

Can you reproduce this with a minimal Junit test that you can paste or link here?

[Academic-123]

while(JinjavaInterpreter.getCurrent() != null) {
    JinjavaInterpreter.popCurrent();
}

Maybe doing this will help.

If there are no other options, then how to make sure that after rendering hostname={{hostname}} is not replaced with hostname= . You must, if the variable in the context is not found, leave the value as was hostname={{hostaname}} ?

[Academic-123]

Can you reproduce this with a minimal Junit test that you can paste or link here?

JUnit4: 4.12
Jinjava: 2.6.0
commons-io: 1.3.2
jackson-annotations: 2.13.2

file with extension .properties

@Test
    public void test() throws IOException {
        while(JinjavaInterpreter.getCurrent() != null) {
            JinjavaInterpreter.popCurrent();
        }
        JinjavaConfig.Builder config = JinjavaConfig.newBuilder();
        config.withFailOnUnknownTokens(true);
        Jinjava jinjava = new Jinjava(config.build());

        RenderResult renderResult = jinjava.renderForResult(Resources.toString(new File(Resources.getResource(
                "test.properties").getPath()).toURI().toURL(), StandardCharsets.UTF_8), new HashMap<>());

        String path = Resources.getResource("test.properties").getPath();
        List<String> linesList = Files.readLines(new File(path), StandardCharsets.UTF_8);

        StringBuilder result = new StringBuilder();
        linesList.forEach((str) -> result.append(str + "\n"));

        System.out.println("expected: " + result);
        System.out.println("actual: " + renderResult.getOutput());
        System.out.println("End");
        Assert.assertEquals(result.toString(), renderResult.getOutput());
    }

[jasmith-hs]

If you want the exception to be thrown, then you'd run:

JinjavaInterpreter interpreter = jinjava.newInterpreter();
interpreter.render(input);

This will throw an UnknownTokenException.

If you're using jinjava.renderForResult(), then the output should be empty and there should be a TemplateError in renderResult.getErrors().

Are you telling me that after running the above code, renderResult.getOutput() contains hostname=?

[Academic-123]

If you want the exception to be thrown, then you'd run:

JinjavaInterpreter interpreter = jinjava.newInterpreter();
interpreter.render(input);

This will throw an UnknownTokenException.

If you're using jinjava.renderForResult(), then the output should be empty and there should be a TemplateError in renderResult.getErrors().

Are you telling me that after running the above code, renderResult.getOutput() contains hostname=?

No, after running the code above renderResult.getOutput() contains an empty value

1. I want the config.withFailOnUnknownTokens(false) flag renderResult.getOutput() to return
   hostname={{hostname}} if the variable is not found instead of hostname= .
2. If the flag is set in config.withFailOnUnknownTokens(true) it threw an error instead of clearing the file, the test above will show

[Academic-123]

If you want the exception to be thrown, then you'd run:

JinjavaInterpreter interpreter = jinjava.newInterpreter();
interpreter.render(input);

This will throw an UnknownTokenException.

If you're using jinjava.renderForResult(), then the output should be empty and there should be a TemplateError in renderResult.getErrors().

Are you telling me that after running the above code, renderResult.getOutput() contains hostname=?

2. Looks like my mistake was because the blank result was written into a file
   renderResult.getOutput()

How do you respond to my first block in the comments above?

[jasmith-hs]

I thought you were wanting it to throw an exception?
If you don't want to throw an exception, and instead leave the expression as-is, you could combine the dynamic variable resolver #572 with using Eager Execution. Use a dynamic variable resolver that maps all string values to a DeferredValue.instance().
You can turn on Eager execution mode by doing config.withExecutionMode(EagerExecutionMode.instance()).
Combining these things will make it so that any value that does not exist on the context will be treated as a deferred value, and it will not be evaluated, which sounds like what you are looking for.
For example if you had:

{% if hostname %}
hostname={{hostname}}
{% else %}
hostname={{ 'none' }}
{% endif %}

the output would be:

{% if hostname %}
hostname={{hostname}}
{% else %}
hostname=none
{% endif %}

[Academic-123]

Я думал, вы хотите, чтобы он выдал исключение? Если вы не хотите генерировать исключение и вместо этого оставляете выражение как есть, вы можете комбинировать преобразователь динамических переменных #572 с использованием Eager Execution. Используйте преобразователь динамических переменных, который сопоставляет все строковые значения с файлом DeferredValue.instance(). Вы можете включить режим выполнения Eager, выполнив config.withExecutionMode(EagerExecutionMode.instance()). Комбинация этих вещей сделает так, что любое значение, которое не существует в контексте, будет рассматриваться как отложенное значение и не будет оцениваться, что звучит как то, что вы ищете. Например, если у вас было:

{% if hostname %}
hostname={{hostname}}
{% else %}
hostname={{ 'none' }}
{% endif %}

вывод будет:

{% if hostname %}
hostname={{hostname}}
{% else %}
hostname=none
{% endif %}

Thank you, that solved my problem

[Academic-123]

I thought you were wanting it to throw an exception? If you don't want to throw an exception, and instead leave the expression as-is, you could combine the dynamic variable resolver #572 with using Eager Execution. Use a dynamic variable resolver that maps all string values to a DeferredValue.instance(). You can turn on Eager execution mode by doing config.withExecutionMode(EagerExecutionMode.instance()). Combining these things will make it so that any value that does not exist on the context will be treated as a deferred value, and it will not be evaluated, which sounds like what you are looking for. For example if you had:

{% if hostname %}
hostname={{hostname}}
{% else %}
hostname={{ 'none' }}
{% endif %}

the output would be:

{% if hostname %}
hostname={{hostname}}
{% else %}
hostname=none
{% endif %}

Hello, and how to make jinjava not fall with the error com.hubspot.jinjava.interpret.UnknownTokenException: Unknown token found: Unclosed comment on variables such as: hostname={#hostname}?

file contains only line hostname={#hostname}

[jasmith-hs]

Hello, and how to make jinjava not fall with the error com.hubspot.jinjava.interpret.UnknownTokenException: Unknown token found: Unclosed comment on variables such as: hostname={#hostname}?

file contains only line hostname={#hostname}

No way to avoid that one. {#hostname} is invalid jinja syntax because {# and #} are used for comments. If you open a comment, you need to close it as well. Jinjava allows you to specify custom token symbols though, so you can remove the comment symbols if you want to, rather than using DefaultTokenScannerSymbols