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void luaD_throw (lua_State *L, int errcode) { if (L->errorJmp) { L->errorJmp->status = errcode; LUAI_THROW(L, L->errorJmp); } else { L->status = cast_byte(errcode); if (G(L)->panic) { resetstack(L, errcode); lua_unlock(L); G(L)->panic(L); } exit(EXIT_FAILURE); } }
期望能 回退 或者 不执行该方法,直接exit 不友好,热修复应该在release下稳定
The text was updated successfully, but these errors were encountered:
把 lua_call 的调用 改成 lua_pcall 即可
lua_call
lua_pcall
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[Bug fix] 改为带保护的lua调用,避免直接 exit Fixes #6
102623b
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期望能 回退 或者 不执行该方法,直接exit 不友好,热修复应该在release下稳定
The text was updated successfully, but these errors were encountered: