Add a method for getting xml node as RawString.

[ikorin24]

Added method(s)

• in U8Xml.XmlNode
  • public RawString AsRawString()

How it works

const string XmlString =
@"<?xml version='1.0' ?>
<a>
  <b>
    <c>foo</c>
  </b>
</a>";


using XmlObject xml = XmlParser.Parse(XmlString);
XmlNode nodeA = xml.Root;              // <a>...</a>
XmlNode nodeB = nodeA.FindChild("b");  // <b>...</b>

RawString nodeString = nodeB.AsRawString();
Console.WriteLine(nodeString);

The output is

<b>
    <c>foo</c>
  </b>

NOTE

The indent of the node is ignored at the head.

[ikorin24]

close #15

[simon-curtis]

🥳 thanks!