%paste regression with blank lines

[jseabold]

I just update to master at 55129be.

I'm able to reproduce with the following code

def other_func(f):
    return f

def some_other_func(f):
    return f

def func(foo):
    foo = some_other_func(foo)

    C = some_other_func(foo)
    # have a blank line
    C = other_func(C)
    return foo

Copy and %paste it into the terminal

## -- End pasted text --
---------------------------------------------------------------------------
NameError                                 Traceback (most recent call last)
<ipython-input-1-f582da7d368d> in <module>()
     11 
     12 
---> 13 C = some_other_func(foo)
     14 # have a blank line
     15 C = other_func(C)

NameError: name 'foo' is not defined  

Then if I do

foo = None
%paste

I get

---------------------------------------------------------------------------
NameError                                 Traceback (most recent call last)
<ipython-input-1-f582da7d368d> in <module>()
     11 
     12 
---> 13 C = some_other_func(foo)
     14 # have a blank line
     15 C = other_func(C)

NameError: name 'foo' is not defined

## -- End pasted text --
---> NameError(Traceback (most recent call last))
---> NameError(: name 'foo' is not defined  )
  File "<ipython-input-8-595d0b69a1da>", line 2
    ---------------------------------------------------------------------------
                                                                               ^
SyntaxError: invalid syntax

Though if I remove the comment line and define at the prompt foo=1 I get a return outside of function

[3]: paste
def other_func(f):
    return f

def some_other_func(f):
    return f

def func(foo):
    foo = some_other_func(foo)

    C = some_other_func(foo)
    C = other_func(C)
    return foo

## -- End pasted text --
  File "<ipython-input-3-77617947b1c7>", line 15
    return foo
SyntaxError: 'return' outside function

[minrk]

@takluyver This is presumably the same as #3178, but the fix in #3202 doesn't cover %paste. A quick fix, I expect?

[takluyver]

Similar, but not quite the same, I think. It looks like it's getting split into multiple cells, so it's trying to execute the block after the blank line separately.

[takluyver]

...the upshot being that it's probably not a trivial fix, but I hope it won't take me too long. I'll look into it shortly.

[cpcloud]

+1 I get this as well

def test_paste(x, y):
    try:
        print x + y
    except:
        z = x + y

    print z
    return x + y

This simple function also does not work.

[minrk]

@cpcloud it doesn't matter that it's a function, it's just that the new input splitter is splitting the cell on blank lines, when it should be taking the whole paste blob, regardless of the contents.

[cpcloud]

I know, just giving another example.

[takluyver]

PR #3390 should fix this.