Fix infinite loop #49
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Fixes infinite loop in case when number or letter appears outside of parentheses. For example: `(add 1 2)5` or `(add 2 3)abs`
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Wait, |
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Sorry, it returns Try this example: That's because |
tailhook
reviewed
Dec 8, 2016
| @@ -423,7 +423,7 @@ function tokenizer(input) { | |||
| // Then we're going to loop through each character in the sequence until | |||
| // we encounter a character that is not a number, pushing each character | |||
| // that is a number to our `value` and incrementing `current` as we go. | |||
| while (NUMBERS.test(char)) { | |||
| while (char && NUMBERS.test(char)) { | |||
There was a problem hiding this comment.
Maybe while(current < input.length && ... ) ?
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may be stupid advice, in the while loop of function tokenizer, there is a let variable named char, but char is a keyword in other language,like c or some others. may be chose another name. |
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it's only a demo, isn't it? |
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Fixes infinite loop in case when number or letter appears outside of parentheses.
/some-regex/.test(undefined)always returns trueFor example:
(add 1 2)5(add 2 3)abs