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Lemma aux2 a0 b0 a b: (forall z, (z | a0) /\ (z | b0) <-> (z | a) /\ (z | b)) ->
a < b ->
forall z, (z | a0) /\ (z | b0) <-> (z | a) /\ (z | b - a).
Proof. (* analogous *)
error here.
Trying to step through to the error sentence marks it red for a fraction of a second but then immediately clears the mark.
The text was updated successfully, but these errors were encountered:
E.g.
Trying to step through to the error sentence marks it red for a fraction of a second but then immediately clears the mark.
The text was updated successfully, but these errors were encountered: