added test to illustrate $ref defining a new scope #327
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Had a discussion about @handrews around this and thought it'd be a good test.
Basically
$ref
provides an additional layer of indirection that maintainsunevaluatedProperties
's inability to see the rest of the schema.So that
becomes
(where
$new-scope
is essentially a no-op, except that it isolates what it contains)rather than
It illustrates how
$ref
resolution behaves when it's adjacent to other keywords.