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Add a setoid with relation given by (x ∈ s ∧ y ∈ s) ∨ x = y and prove basic properties.
(x ∈ s ∧ y ∈ s) ∨ x = y
Motivation: quotients of this type are common in counterexamples in topology.
See also Zulip chat
The text was updated successfully, but these errors were encountered:
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Add a setoid with relation given by
(x ∈ s ∧ y ∈ s) ∨ x = y
andprove basic properties.
Motivation: quotients of this type are common in counterexamples in
topology.
See also Zulip chat
The text was updated successfully, but these errors were encountered: