Given the root
of a binary tree, invert the tree, and return its root.
Example 1:
Input: root = [4,2,7,1,3,6,9]
Output: [4,7,2,9,6,3,1]
Example 2:
Input: root = [2,1,3]
Output: [2,3,1]
Example 3:
Input: root = []
Output: []
Constraints:
- The number of nodes in the tree is in the range
[0, 100]
. 100 <= Node.val <= 100
題目給定一個二元樹的 root
實作一個演算法把數中所有原本左邊的結點換成右邊的結點
已知每個結點都由左結點與右邊結點組成
所以 要反轉整個樹的左右結點等於 把root 的左右結點互換 + 原本左子樹做反轉 + 原本右子樹做反轉
/**
* Definition for a binary tree node.
* type TreeNode struct {
* Val int
* Left *TreeNode
* Right *TreeNode
* }
*/
func invertTree(root *TreeNode) *TreeNode {
if root == nil {
return nil
}
root.Left, root.Right = root.Right, root.Left
if root.Left != nil {
invertTree(root.Left)
}
if root.Right != nil {
invertTree(root.Right)
}
return root
}
- 看出每個轉換結點的遞迴關係
- Understand what problem would like to solve
- Analysis Complexity