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[DependenceAnalysis] Make sure base objects are the same when compari…
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…ng GEPs

The dependence analysis was returning incorrect information when using the GEPs
to compute dependences. The analysis uses the GEP indices under certain
conditions, but was doing it incorrectly when the base objects of the GEP are
aliases, but pointing to different locations in the same array.

This patch adds another check for the base objects. If the base pointer SCEVs
are not equal, then the dependence analysis should fall back on the path
that uses the whole SCEV for the dependence check. This fixes PR33567.

Differential Revision: https://reviews.llvm.org/D34702

llvm-svn: 307203
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Brendon Cahoon committed Jul 5, 2017
1 parent c0fe1f2 commit cb8c7b9
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3 changes: 2 additions & 1 deletion llvm/lib/Analysis/DependenceAnalysis.cpp
Original file line number Diff line number Diff line change
Expand Up @@ -3342,7 +3342,8 @@ DependenceInfo::depends(Instruction *Src, Instruction *Dst,

UsefulGEP = isLoopInvariant(SrcPtrSCEV, LI->getLoopFor(Src->getParent())) &&
isLoopInvariant(DstPtrSCEV, LI->getLoopFor(Dst->getParent())) &&
(SrcGEP->getNumOperands() == DstGEP->getNumOperands());
(SrcGEP->getNumOperands() == DstGEP->getNumOperands()) &&
isKnownPredicate(CmpInst::ICMP_EQ, SrcPtrSCEV, DstPtrSCEV);
}
unsigned Pairs = UsefulGEP ? SrcGEP->idx_end() - SrcGEP->idx_begin() : 1;
SmallVector<Subscript, 4> Pair(Pairs);
Expand Down
80 changes: 80 additions & 0 deletions llvm/test/Analysis/DependenceAnalysis/BasePtrBug.ll
Original file line number Diff line number Diff line change
@@ -0,0 +1,80 @@
; RUN: opt < %s -analyze -basicaa -da | FileCheck %s

; Test that the dependence analysis generates the correct results when using
; an aliased object that points to a different element in the same array.
; PR33567 - https://bugs.llvm.org/show_bug.cgi?id=33567

; void test1(int *A, int *B, int N) {
; int *top = A;
; int *bot = A + N/2;
; for (int i = 0; i < N; i++)
; B[i] = top[i] + bot[i];
; }

; CHECK-LABEL: test1
; CHECK: da analyze - input [*|<]!

define void @test1(i32* nocapture %A, i32* nocapture %B, i32 %N) #0 {
entry:
%cmp9 = icmp sgt i32 %N, 0
br i1 %cmp9, label %for.body.lr.ph, label %for.end

for.body.lr.ph:
%div = sdiv i32 %N, 2
%bot.gep = getelementptr i32, i32* %A, i32 %div
br label %for.body

for.body:
%i = phi i32 [ 0, %for.body.lr.ph ], [ %inc, %for.body ]
%gep.0 = getelementptr i32, i32* %A, i32 %i
%gep.1 = getelementptr i32, i32* %bot.gep, i32 %i
%gep.B = getelementptr i32, i32* %B, i32 %i
%0 = load i32, i32* %gep.0, align 4
%1 = load i32, i32* %gep.1, align 4
%add = add nsw i32 %1, %0
store i32 %add, i32* %gep.B, align 4
%inc = add nsw i32 %i, 1
%exitcond = icmp eq i32 %inc, %N
br i1 %exitcond, label %for.end, label %for.body

for.end:
ret void
}


; void test2(int *A, unsigned n) {
; int *B = A + 1;
; for (unsigned i = 0; i < n; ++i) {
; A[i] = B[i];
; }
; }

; CHECK-LABEL: test2
; CHECK: da analyze - consistent anti [1]!

define void @test2(i32*, i32) #3 {
%3 = getelementptr inbounds i32, i32* %0, i64 1
br label %4

; <label>:4:
%.0 = phi i32 [ 0, %2 ], [ %14, %13 ]
%5 = sub i32 %1, 1
%6 = icmp ult i32 %.0, %5
br i1 %6, label %7, label %15

; <label>:7:
%8 = zext i32 %.0 to i64
%9 = getelementptr inbounds i32, i32* %3, i64 %8
%10 = load i32, i32* %9, align 4
%11 = zext i32 %.0 to i64
%12 = getelementptr inbounds i32, i32* %0, i64 %11
store i32 %10, i32* %12, align 4
br label %13

; <label>:13:
%14 = add i32 %.0, 1
br label %4

; <label>:15:
ret void
}

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