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bus.subscribe({ routingKey: 'foo.bar', queueName: `${process.env.
SERVICE_NAME_OR_SOMETHING_LIKE_IT}-foo.bar` }, options, (msg) => {
});
If you use servicebus-register-handlers, there is a queuePrefix property to
do the same thing globally on all subscribes.
On Fri, Mar 3, 2017, 2:00 PM aangelidis ***@***.***> wrote:
Unless I missed something, the queues are completely managed by servicebus.
bus.subscribe('foo.bar', options, (msg) => {
});
This will create a queue as foo.bar.8aadae7d-bd7e-4dc7-ba85-f57a102b06fe.
Is it possible to tell it to use an existing queue?
For instance we want to pre create the queue let it fill up and when the
application finished loading it then starts to read the queue.
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.
Unless I missed something, the queues are completely managed by servicebus.
bus.subscribe('foo.bar', options, (msg) => {
});
This will create a queue as foo.bar.8aadae7d-bd7e-4dc7-ba85-f57a102b06fe.
Is it possible to tell it to use an existing queue?
For instance we want to pre create the queue let it fill up and when the application finished loading it then starts to read the queue.
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