improvement: Fix grammar in error an message

medleyjs · Jun 23, 2019 · b04a8ea · b04a8ea
1 parent 92208f4
commit b04a8ea
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Showing 2 changed files with 9 additions and 4 deletions.
diff --git a/medley.js b/medley.js
@@ -28,7 +28,7 @@ function medley(options) {
   options = options || {}
 
   if (options.queryParser !== undefined && typeof options.queryParser !== 'function') {
-    throw new TypeError(`'queryParser' option must be an function. Got a '${typeof options.queryParser}'`)
+    throw new TypeError(`'queryParser' option must be a function. Got value of type '${typeof options.queryParser}'`)
   }
 
   const router = findMyWay({

diff --git a/test/queryParser-option.test.js b/test/queryParser-option.test.js
@@ -5,16 +5,21 @@ const medley = require('..')
 const request = require('./utils/request')
 
 t.test('queryParser', (t) => {
-  t.plan(6)
+  t.plan(7)
 
   t.throws(
     () => medley({queryParser: true}),
-    new TypeError("'queryParser' option must be an function. Got a 'boolean'")
+    new TypeError("'queryParser' option must be a function. Got value of type 'boolean'")
   )
 
   t.throws(
     () => medley({queryParser: 'simple'}),
-    new TypeError("'queryParser' option must be an function. Got a 'string'")
+    new TypeError("'queryParser' option must be a function. Got value of type 'string'")
+  )
+
+  t.throws(
+    () => medley({queryParser: []}),
+    new TypeError("'queryParser' option must be a function. Got value of type 'object'")
   )
 
   const app = medley({