confuse with int

[lpnueg4]

from addict import Dict as dd

a = dd()

a.a.a[0] = 1
a.a.a[0] = 123 # here 0 is a key
print a # {'a': {'a': {0: 123}}}

a = dd()
a.a.a = [1,2,3]
a.a.a[0] = 'asd' # here 0 is a index
print a # {'a': {'a': ['asd', 2, 3]}}

How to handle this thing? if not read context, nobody know '0' is a key or a index.

[mewwts]

Hi @lpnueg4,
Code is best read with context. In your second example, you explicitly set a.a.a to be a list, hence I don't see a problem with addict here. In fact, you could create the equivalent example with a normal dictionary

>>> a = {'a': {'a': {0: 1}}}
>>> a['a']['a'][0] = 123 # here 0 is a key
>>> print(a)
{'a': {'a': {0: 123}}}

>>> a = {'a': {'a': [1, 2, 3]}}
>>> a['a']['a'][0] = 'asd' # here 0 is an index
>>> print(a)
{'a': {'a': ['asd', 2, 3]}}

and it would be the same?