Namespaced modules' path broken when code is minified

[aymasse]

Hello,

While using version 2.0.4, module declaration is kind of broken in minified code due to the path being pulled from the class' name.
Problem is, the class name is being mangled while using vue-cli in its default configuration.

The result (for me) is that my store only has a single module (named t in my output), even if I declare several modules. This single module contains every state property of my modules but only the mutations and actions of the last declared one.

[SaphuA]

For now define your stores the old way:

@Module({ namespacedPath: "foo" })
export default class extends VuexModule { }

You can still define your Vuex-store the new way:

import FooStore from "@/foo/store";
const modules = { ...extractVuexModule(FooStore) };
export const store = new Vuex.Store({ modules });

[danielroe]

I've closed #42 as it's another expression of this issue - thanks to @SaphuA for the workaround.

If it's useful, see see my repro - and run yarn build && yarn start.

[vizv]

From

vuex-class-component/src/module.ts

Line 89 in 24ed31b

cls.prototype.__namespacedPath__ = cls.prototype.__options__.namespaced.split("/")[0]

I think you setting namespaced to a string should work.

const VuexModule = createModule({
  namespaced: 'foo',
  strict: false,
  target: "nuxt",
})

[michaelolof]

Hello @aymasse

I've made an update based on the issue raised.
Thanks to @vizv 's suggestion

interface VuexModuleOptions {
  namespaced ?:string;
  ...
}

I've modified the namespaced option to take only a string.

[SaphuA]

works perfectly now