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Namespaced modules' path broken when code is minified #43

aymasse opened this issue Sep 12, 2019 · 5 comments


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@aymasse aymasse commented Sep 12, 2019


While using version 2.0.4, module declaration is kind of broken in minified code due to the path being pulled from the class' name.
Problem is, the class name is being mangled while using vue-cli in its default configuration.

The result (for me) is that my store only has a single module (named t in my output), even if I declare several modules. This single module contains every state property of my modules but only the mutations and actions of the last declared one.


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@SaphuA SaphuA commented Sep 30, 2019

For now define your stores the old way:

@Module({ namespacedPath: "foo" })
export default class extends VuexModule { }

You can still define your Vuex-store the new way:

import FooStore from "@/foo/store";
const modules = { ...extractVuexModule(FooStore) };
export const store = new Vuex.Store({ modules });

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@danielroe danielroe commented Oct 5, 2019

I've closed #42 as it's another expression of this issue - thanks to @SaphuA for the workaround.

If it's useful, see see my repro - and run yarn build && yarn start.


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@vizv vizv commented Oct 22, 2019


cls.prototype.__namespacedPath__ = cls.prototype.__options__.namespaced.split("/")[0]

I think you setting namespaced to a string should work.

const VuexModule = createModule({
  namespaced: 'foo',
  strict: false,
  target: "nuxt",

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@michaelolof michaelolof commented Nov 10, 2019

Hello @aymasse

I've made an update based on the issue raised.
Thanks to @vizv 's suggestion

interface VuexModuleOptions {
  namespaced ?:string;

I've modified the namespaced option to take only a string.


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@SaphuA SaphuA commented Nov 11, 2019

works perfectly now

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