coinductive version of always #113
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| @@ -50,4 +50,14 @@ Section Combinators. | |||
| (Preserve: forall s, invariant s -> step s invariant) | |||
| (Use: forall s, invariant s -> P s). | |||
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| CoInductive always' (P : State -> Prop) (s : State) : Prop := | |||
| always'_step { hd_always' : P s; tl_always' : step s (always P) }. | |||
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In the recursive invocation in tl_always', you use the Inductive always, not the CoInductive, is this intended? (simply replacing always by always' doesn't work because non-strictly positive occurrence). If it is intended, could you add introduction and elimination rules that pretend the Inductive doesn't exist, and express everything in terms of the CoInductive?
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Yes I intended an independent definition; trying again.
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please fast-forward for mit-plv/fiat-crypto#1846