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If the Russian roulette termination probability at each sampled point is set to be equal to the ratio of σn and σmaj, then the scaling cancels and the estimator becomes
->
termination probability should be 1 - ratio of σn and σmaj
code also using termination probability 1 - σn / σmaj
simple path trace, direct light evaluate 13.9,
P(pi¯) = Le(pi -> pi-1) * f(pi -> pi-1 -> pi-2) * |cosθi| * V(pi <->pi-1) / (pl(wi) * p(l)) * β
here cosθi should be angle on shading surface, so cosθi-1
the code also using shading point angle.
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