Fix taylor factorial

mooculus · Oct 22, 2018 · e44392d · e44392d
1 parent 5f2891a
commit e44392d
Showing 1 changed file with 1 addition and 1 deletion.
diff --git a/introductionToTaylorSeries/exercises/higherOrderDerivative1.tex b/introductionToTaylorSeries/exercises/higherOrderDerivative1.tex
@@ -104,7 +104,7 @@
 Thus:
 
 \[
-a_{95} = 3 \cdot \frac{(-1)^k}{(2k)!}  \bigg|_{k=15} = \frac{\answer{-3}}{(\answer{30})}!
+a_{95} = 3 \cdot \frac{(-1)^k}{(2k)!}  \bigg|_{k=15} = \frac{\answer{-3}}{(\answer{30})!}
 \]
 
 and the formula $a_{95} = \frac{f^{(95)}(0)}{95!}$ gives that: