split_before confuse me

[ghost]

The docs says split_before

Yield lists of items from iterable, where each list starts with an item where callable pred returns True

But why below returns

In [3]: list(split_before(range(1, 10), lambda n: n % 3 == 0))
Out[3]: [[1, 2], [3, 4, 5], [6, 7, 8], [9]]

Rather than returns

In [3]: list(split_before(range(1, 10), lambda n: n % 3 == 0))
Out[3]: [[3, 4, 5], [6, 7, 8], [9]]

What i`m got wrong ? Thanks in advance

[bbayles]

Thanks for the note. You're right; I should change the docstring to be more accurate. No items are skipped by split_before.

[ghost]

Thanks for your reply, it solves my question.

[failable]

I've thought that list(split_before('OneTwo', lambda s: s.isupper())) will return [[''], ['O', 'n', 'e'], ['T', 'w', 'o']]...