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# Given n, how many structurally unique BST's (binary search trees) that store values 1...n? | ||
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# For example, | ||
# Given n = 3, there are a total of 5 unique BST's. | ||
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# 1 3 3 2 1 | ||
# \ / / / \ \ | ||
# 3 2 1 1 3 2 | ||
# / / \ \ | ||
# 2 1 2 3 | ||
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class Solution: | ||
# @return an integer | ||
def numTrees(self, n): | ||
num = [0]*(n+1) | ||
if n == 0: | ||
return 1 | ||
if n == 1: | ||
return 1 | ||
num[0] = 1 | ||
num[1] = 1 | ||
for i in range(2,n+1): | ||
for j in range(0,i): | ||
num[i] += num[j] * num[i-j-1] | ||
return num[-1] | ||
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