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peak() and peek_next() calls source.chars().nth(x). Is this idiomatic way to get n-th char in a string?
peak()
peek_next()
source.chars().nth(x)
The text was updated successfully, but these errors were encountered:
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peak()
andpeek_next()
callssource.chars().nth(x)
. Is this idiomatic way to get n-th char in a string?The text was updated successfully, but these errors were encountered: