Define (**) for AD type explicitly #4
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Using implicit definition x ** y = exp (log x * y) makes its gradient to be [(y * exp (log x * y)) / x, log x * exp (log x * y)] and its problematic when x = 0.
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Thank you! |
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@msakai available from v 0.5 : https://hackage.haskell.org/package/ad-delcont-0.5.0.0 |
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Using implicit definition
makes its gradient to be
and it's problematic when
x = 0.