[E] optimized group join-requests counter #2067
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Logic: Every approved member MUST HAVE a group:join record already, and so we can count them indirectly by counting the group:join:approved records. Now, if we do a second count on group:join records, the difference between the first and the second count is exactly the number of not yet approved members. If the difference = 0, every member must have been approved. :)
lianglee
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Logic:
Every approved member MUST HAVE a group:join record already, and so we can count them indirectly by counting the group:join:approved records.
Now, if we do a second count on group:join records, the difference between the first and the second count is exactly the number of not yet approved members.
If the difference = 0, every member must have been approved. :)