Version 4 SHEET 1 2060 780 WIRE -512 16 -608 16 WIRE -512 96 -512 16 WIRE 96 112 96 96 WIRE -64 144 -80 144 WIRE 96 208 96 192 WIRE -512 256 -512 176 WIRE -480 256 -512 256 WIRE -512 336 -512 256 WIRE -512 496 -512 416 WIRE -512 496 -608 496 WIRE -240 496 -512 496 WIRE -80 496 -160 496 WIRE 80 496 0 496 WIRE -512 560 -512 496 WIRE -512 704 -512 640 FLAG 80 496 O IOPIN 80 496 BiDir FLAG -608 16 A IOPIN -608 16 BiDir FLAG -608 496 B IOPIN -608 496 BiDir FLAG -80 144 D IOPIN -80 144 In FLAG -480 256 0 FLAG -512 704 0 FLAG 96 208 0 FLAG 96 96 D1 SYMBOL bv -144 496 R90 WINDOW 0 -32 56 VBottom 2 WINDOW 3 32 56 VTop 2 SYMATTR InstName VOB SYMATTR Value V=V(D1)*V(A,B) SYMBOL bi -512 96 R0 SYMATTR InstName IA SYMATTR Value I=V(D1)*I(VIO) SYMBOL bi -512 416 M180 WINDOW 0 24 80 Left 2 WINDOW 3 24 0 Left 2 SYMATTR InstName IB SYMATTR Value I=(1-V(D1))*I(VIO) SYMBOL voltage -96 496 R270 WINDOW 0 32 56 VTop 2 WINDOW 3 -32 56 VBottom 2 SYMATTR InstName VIO SYMATTR Value 0 SYMBOL bi -512 560 R0 SYMATTR InstName IBx SYMATTR Value I=I(VOB) SYMBOL bv 96 96 R0 WINDOW 0 24 16 Invisible 2 SYMATTR InstName VD SYMATTR Value V=V(D)/2+0.5 TEXT -184 624 Left 2 ;IA, IB and VOB follow converter average equations\nIBx compensates VLB current so it is not added to IB port\nVIO is a sensor for IO current