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When plotting with a TimedeltaIndex with a fixed frequency and xmin > xmax, a ValueError gets raised.
TimedeltaIndex
xmin > xmax
>>> pd.Series([1,2], index=pd.timedelta_range(start=0, periods=2, freq='D')).plot(xlim=(3, 1))
C:\ProgramData\Miniconda3\envs\env_name\lib\site-packages\pandas\plotting_matplotlib\converter.py in call(self, x, pos) 1066 def call(self, x, pos=0) -> str: 1067 (vmin, vmax) = tuple(self.axis.get_view_interval()) -> 1068 n_decimals = int(np.ceil(np.log10(100 * 1e9 / (vmax - vmin)))) 1069 if n_decimals > 9: 1070 n_decimals = 9 ValueError: cannot convert float NaN to integer
C:\ProgramData\Miniconda3\envs\env_name\lib\site-packages\pandas\plotting_matplotlib\converter.py in call(self, x, pos) 1066 def call(self, x, pos=0) -> str: 1067 (vmin, vmax) = tuple(self.axis.get_view_interval()) -> 1068 n_decimals = int(np.ceil(np.log10(100 * 1e9 / (vmax - vmin)))) 1069 if n_decimals > 9: 1070 n_decimals = 9
ValueError: cannot convert float NaN to integer
Seems that there should just be an abs in this line.
abs
I would expect this to be able to output a plot successfully.
Works fine with a TimedeltaIndex with freq=None:
freq=None
pd.Series([1,2], index=[pd.Timedelta(days=1), pd.Timedelta(days=2)]).plot(xlim=(3, 1))
commit : db08276 python : 3.8.6.final.0 python-bits : 64 OS : Windows OS-release : 10 Version : 10.0.18362 machine : AMD64 processor : Intel64 Family 6 Model 94 Stepping 3, GenuineIntel byteorder : little LC_ALL : None LANG : None LOCALE : English_United States.1252
pandas : 1.1.3 numpy : 1.19.2 pytz : 2020.1 dateutil : 2.8.1 pip : 20.2.3 setuptools : 49.6.0.post20201009 Cython : None pytest : 6.1.1 hypothesis : None sphinx : 3.2.1 blosc : None feather : None xlsxwriter : None lxml.etree : None html5lib : None pymysql : None psycopg2 : 2.8.6 (dt dec pq3 ext lo64) jinja2 : 2.11.2 IPython : 7.18.1 pandas_datareader: None bs4 : None bottleneck : None fsspec : None fastparquet : None gcsfs : None matplotlib : 3.3.2 numexpr : 2.7.1 odfpy : None openpyxl : None pandas_gbq : None pyarrow : 1.0.1 pytables : None pyxlsb : None s3fs : None scipy : 1.5.0 sqlalchemy : 1.3.20 tables : 3.6.1 tabulate : None xarray : None xlrd : None xlwt : None numba : None
The text was updated successfully, but these errors were encountered:
BUG: Fix for #37454: allow reversed axis when plotting with Timedelta…
79a184a
…Index (#37469)
Successfully merging a pull request may close this issue.
When plotting with a
TimedeltaIndex
with a fixed frequency andxmin > xmax
, a ValueError gets raised.Seems that there should just be an
abs
in this line.I would expect this to be able to output a plot successfully.
Works fine with a
TimedeltaIndex
withfreq=None
:INSTALLED VERSIONS
commit : db08276
python : 3.8.6.final.0
python-bits : 64
OS : Windows
OS-release : 10
Version : 10.0.18362
machine : AMD64
processor : Intel64 Family 6 Model 94 Stepping 3, GenuineIntel
byteorder : little
LC_ALL : None
LANG : None
LOCALE : English_United States.1252
pandas : 1.1.3
numpy : 1.19.2
pytz : 2020.1
dateutil : 2.8.1
pip : 20.2.3
setuptools : 49.6.0.post20201009
Cython : None
pytest : 6.1.1
hypothesis : None
sphinx : 3.2.1
blosc : None
feather : None
xlsxwriter : None
lxml.etree : None
html5lib : None
pymysql : None
psycopg2 : 2.8.6 (dt dec pq3 ext lo64)
jinja2 : 2.11.2
IPython : 7.18.1
pandas_datareader: None
bs4 : None
bottleneck : None
fsspec : None
fastparquet : None
gcsfs : None
matplotlib : 3.3.2
numexpr : 2.7.1
odfpy : None
openpyxl : None
pandas_gbq : None
pyarrow : 1.0.1
pytables : None
pyxlsb : None
s3fs : None
scipy : 1.5.0
sqlalchemy : 1.3.20
tables : 3.6.1
tabulate : None
xarray : None
xlrd : None
xlwt : None
numba : None
The text was updated successfully, but these errors were encountered: