[euler] pod formating

categories/euler/prob065-andreoss.pl

@@ -10,33 +10,33 @@
 
 The square root of 2 can be written as an infinite continued fraction.
 
-√2 = 1 +  1
-        ______
-	2 +  1
-           ______
-  	   2 + 	1
-  	      ______
-	      2 +  1
-  	  	 ______
-	         2 + ...
-
+	√2 = 1 +  1
+	        ______
+		2 +  1
+	           ______
+	  	   2 + 	1
+	  	      ______
+		      2 +  1
+	  	  	 ______
+		         2 + ...
+	
 The infinite continued fraction can be written, √2 = [1;(2)], (2) indicates
 that 2 repeats ad infinitum. In a similar way, √23 = [4;(1,3,1,8)].
 
 It turns out that the sequence of partial values of continued fractions for
 square roots provide the best rational approximations. Let us consider the
 convergents for √2.
-
-1 + 1
-   ___              = 3/2
-    2
-
-1 +    1
-    _________       = 7/5
-    2 +  1 / 2
-
-....
-
+	
+	1 + 1
+	   ___              = 3/2
+	    2
+	
+	1 +    1
+	    _________       = 7/5
+	    2 +  1 / 2
+	
+	....
+	
 Hence the sequence of the first ten convergents for √2 are: 1, 3/2, 7/5,
 17/12, 41/29, 99/70, 239/169, 577/408, 1393/985, 3363/2378, ...
 

categories/euler/prob066-andreoss.pl

@@ -8,9 +8,7 @@
 
 L<https://projecteuler.net/problem=66>
 
-Consider quadratic Diophantine equations of the form:
-
-x² – D×y² = 1
+Consider quadratic Diophantine equations of the form: x² – D×y² = 1
 
 For example, when D=13, the minimal solution in x is 649² – 13×180² = 1.
 
@@ -20,12 +18,16 @@
 By finding minimal solutions in x for D = {2, 3, 5, 6, 7}, we obtain the
 following:
 
-3²– 2×2²= 1
-2²– 3×1²= 1
-9²– 5×4²= 1
-5²– 6×2²= 1
-8²– 7×3²= 1
+3² – 2×2²= 1
+
+2² – 3×1²= 1
+
+9² – 5×4²= 1
+
+5² – 6×2²= 1
 
+8² – 7×3²= 1
+	
 Hence, by considering minimal solutions in x for D ≤ 7, the largest x is
 obtained when D=5.