[S03, S12] ^Dog no longer means Dog.HOW

Use the Dog.^foo form when you want to call methods on Dog's metaclass.

This makes prefix:<^> unambiguously mean 0 ..^ $something, with no
weird exception for type objects.

S03-operators.pod

@@ -15,8 +15,8 @@ Synopsis 3: Perl 6 Operators
 
     Created: 8 Mar 2004
 
-    Last Modified: 1 Jan 2012
-    Version: 234
+    Last Modified: 14 Jan 2012
+    Version: 235
 
 =head1 Overview
 
@@ -3533,10 +3533,6 @@ The unary C<^> operator generates a range from C<0> up to
 
     for ^4 { say $_ } # 0, 1, 2, 3
 
-If applied to a type name, it indicates the metaclass instance instead,
-so C<^Moose> is short for C<HOW(Moose)> or C<Moose.HOW>.  It still kinda
-means "what is this thing's domain" in an abstract sort of way.
-
 =head2 Auto-priming of ranges
 
 [This section is conjectural, and may be ignored for 6.0.]

S12-objects.pod

@@ -13,8 +13,8 @@ Synopsis 12: Objects
 
     Created: 27 Oct 2004
 
-    Last Modified: 19 Sep 2011
-    Version: 123
+    Last Modified: 14 Jan 2012
+    Version: 124
 
 =head1 Overview
 
@@ -185,10 +185,6 @@ may tell you that they are defined, while others may tell you that
 they are undefined.  That's up to the object, and depends on how the
 metaclass chooses to dispatch the C<.defined> method.
 
-The notation C<^Dog> is syntactic sugar for C<Dog.HOW()>, so C<^> can be
-considered the "class" sigil when you want to talk about the current
-metaclass instance.
-
 =head2 Closed classes
 
 Classes are open and non-final by default, but may easily be closed
@@ -2313,7 +2309,6 @@ of the class:
 The C<^> metasyntax is equivalent to C<.HOW>:
 
     MyClass.HOW.methods($obj)   # get the method list of MyClass
-    ^MyClass.methods($obj)      # get the method list of MyClass
     MyClass.^methods()          # get the method list of MyClass
 
 Each object of the class also has a C<.HOW> or C<.^> method: