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a key in rows is not defined. this snippet should fix it:
$stmt = $this->dbh->query("SELECT ccu1.TABLE_NAME, ccu1.COLUMN_NAME, ccu2.TABLE_NAME AS FK_TABLE_NAME, ccu2.COLUMN_NAME AS FK_COLUMN_NAME, ccu2.CONSTRAINT_NAME AS FK_NAME FROM INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE ccu1 INNER JOIN INFORMATION_SCHEMA.TABLE_CONSTRAINTS tc1 ON tc1.CONSTRAINT_NAME = ccu1.CONSTRAINT_NAME AND CONSTRAINT_TYPE = 'Foreign Key' INNER JOIN INFORMATION_SCHEMA.REFERENTIAL_CONSTRAINTS rc1 ON rc1.CONSTRAINT_NAME = tc1.CONSTRAINT_NAME INNER JOIN INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE ccu2 ON ccu2.CONSTRAINT_NAME = rc1.UNIQUE_CONSTRAINT_NAME WHERE (ccu1.table_name = '".$table->getName()."')"); $foreignKeys = array(); // local store to avoid duplicates while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) { $lcol = $row['COLUMN_NAME']; $ftbl = $row['FK_TABLE_NAME']; $fcol = $row['FK_COLUMN_NAME']; $name = $row['FK_NAME'];
The text was updated successfully, but these errors were encountered:
When do you see a warning? How to reproduce? Which line is fixed with your snippet in whichfile?
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The current source is below. The variable $name is not defined. My code selects an extra column, FK_NAME, and assigns the variable.
while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) { $lcol = $this->cleanDelimitedIdentifiers($row['COLUMN_NAME']); $ftbl = $this->cleanDelimitedIdentifiers($row['FK_TABLE_NAME']); $fcol = $this->cleanDelimitedIdentifiers($row['FK_COLUMN_NAME']); $foreignTable = $database->getTable($ftbl); $foreignColumn = $foreignTable->getColumn($fcol); $localColumn = $table->getColumn($lcol); if (!isset($foreignKeys[$name])) {
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a key in rows is not defined. this snippet should fix it:
The text was updated successfully, but these errors were encountered: