Request: page.html()

[RobertCorey]

Return the html of the current page. Is there an easy way to do this I'm not seeing?

[RobertCorey]

I see how to do it now https://github.com/GoogleChrome/puppeteer/blob/master/examples/search.js . I will write an example and submit a pr for the readme.

[ebidel]

See #331 (comment)

[alex88]

If you want a more complete html, including doctype and html tag (which I think is the real page html, not the innerhtml) you can use

const renderedContent = await page.evaluate(() => new XMLSerializer().serializeToString(document));

[ebidel]

If you want to minimize the alterations added by XMLSerializer:

const html = await page.evaluate('new XMLSerializer().serializeToString(document.doctype) + document.documentElement.outerHTML');

[hasibsahibzada]

Simple just use

const html = await page.content();