UnboundLocalError when I try to get column family

[spoksss]

Hi,

I have just started with cassandra, so don't know if this should be realy reported as a bug,

If one try to get column family but haven't created that column family/keyspace
using pycassaShell will get error,

>>> keyspace = "test_ks"
>>> column_family = "test_cf"
>>> pool = pycassa.connect(keyspace)
>>> col_fam = pycassa.ColumnFamily(pool, column_family)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "pycassa/columnfamily.py", line 252, in __init__
    self.load_schema()
  File "pycassa/columnfamily.py", line 269, in load_schema
    use_dict_for_col_metadata=True)
  File "pycassa/pool.py", line 573, in execute
    self.put(conn)
UnboundLocalError: local variable 'conn' referenced before assignment

I got this error, checked what happen and I created keyspace and column family,
and haven't got that error again,

pycassaShell
[I]: IPython not found, falling back to default interpreter.
----------------------------------
Cassandra Interactive Python Shell
---------------------------------- 
Keyspace: None
Host: localhost:9160

 ColumnFamily instances are only available if a keyspace is specified with -k/--keyspace

Schema definition tools and cluster information are available through SYSTEM_MANAGER.
>>> SYSTEM_MANAGER.create_keyspace('test_ks', replication_factor=1)
>>> SYSTEM_MANAGER.create_column_family('test_ks','test_cf')
>>>

>>> pool = pycassa.connect(keyspace) 
>>> col_fam = pycassa.ColumnFamily(pool, column_family)
>>> row_id_1 = "1"
>>> col_fam.insert(row_id_1, {'name':'Some name'})

My env:
python: 2.6.5
cassandra: 0.8.6
pycassa: 1.2.0

[thobbs]

Thanks!